C Program to display the No. of Digits in an Entered Number

Submitted by Srikanth on Monday, 3 December 20073 Comments

This program displays the number of digits present in the number that is entered through the input.

#include<stdio.h>
#include<conio.h>

void main()
{
unsigned long int num;
int i=0;
clrscr();
printf(“Enter the digit\n”);
scanf(“%lu”,&num);
while(num!=0)
{
num=num/10;
++i;
}
printf(“Length=%d”,i);
getch();
}

3 Comments »

OSBAMA said:

I DON’T KNOW WHAT KIND OF COMPILER DO YOU HAVE, BUT DEV REPORTS 4 OR 5 5 MISTAKES. WHY IS THAT HAPPENING.

- 5 October 2010 at 9:22 PM

TanzeelurRehman said:

@osbama,

Basically when you copy the program and use in Dev C++, then do following things
1) use int main instead of void main
2) Remove clrscr();
3) Correct the qoutes (“”), where ever in the program, Dev C++ doesnot recognize them as a qoute.

and then you will have your programe working

Regards
TanzeelurRehman

- 3 April 2011 at 12:34 PM

alex said:

and it can’t display more than 10…
example… you input “54654651651654″, and the program says “Length=10″

- 7 November 2011 at 12:15 AM

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