C Program to Print the Entered Number in Words
Submitted by Srikanth on Tuesday, 4 December 20074 Comments
The following C program print’s the entered number in words. For example if the number entered is 12345 then the program prints the entered number in words as One Two Three Four Five
#include<stdio.h>
void main()
{
int i=0;
unsigned long int digit;
char str[12],ch;
puts(“Enter the number (less than 10 digit)”);
scanf(“%lu”,&digit);
ultoa(digit,str,10); /*converts an unsigned long int to string*/
while(str[i]!=’\0′)
{
ch=str[i];
i++;
switch(ch)
{
case ’1′:
printf(“ONE “);
break;
case ’2′:
printf(“TWO “);
break;
case ’3′:
printf(“THREE “);
break;
case ’4′:
printf(“FOUR “);
break;
case ’5′:
printf(“FIVE “);
break;
case ’6′:
printf(“SIX “);
break;
case ’7′:
printf(“SEVEN “);
break;
case ’8′:
printf(“EIGHT “);
break;
case ’9′:
printf(“NINE “);
break;
case ’0′:
printf(“ZERO “);
break;
}
}
}
void main()
{
int i=0;
unsigned long int digit;
char str[12],ch;
puts(“Enter the number (less than 10 digit)”);
scanf(“%lu”,&digit);
ultoa(digit,str,10); /*converts an unsigned long int to string*/
while(str[i]!=’\0′)
{
ch=str[i];
i++;
switch(ch)
{
case ’1′:
printf(“ONE “);
break;
case ’2′:
printf(“TWO “);
break;
case ’3′:
printf(“THREE “);
break;
case ’4′:
printf(“FOUR “);
break;
case ’5′:
printf(“FIVE “);
break;
case ’6′:
printf(“SIX “);
break;
case ’7′:
printf(“SEVEN “);
break;
case ’8′:
printf(“EIGHT “);
break;
case ’9′:
printf(“NINE “);
break;
case ’0′:
printf(“ZERO “);
break;
}
}
}
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Hi Srikanth,
How to print figures in Words? Like 1500 will be printed as “Fifteen hundred”, 10205 will be printed as “Ten thousand two hundred five”.
Please mail me the code in “C” ASAP.
Thanks,
Sony
How to use this code ? What extensino do we have to put ?
@ me
Save the program in a notepad and change the extension from .txt to .c
i want program which print no given by user in words
example:= 1999:=one thousand nine hundred ninty nine.
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