C Program to Print a Character without using any Output Statements
Submitted by Srikanth on Sunday, 25 November 20076 Comments
This program can be used to print character without using any output statements. This program only works in 16-bit mode since it directly writes to VDU Memory.
#include<stdio.h>
#include<conio.h>
void main()
{
char far *p=(char far *)0xb8000000;
*p=’A';
getch();
}
#include<conio.h>
void main()
{
char far *p=(char far *)0xb8000000;
*p=’A';
getch();
}
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it gives an error saying
“cannot convert unsigned long to char far*”
try this
char far *p=(char far*)0xb8000000;
1 error C2143: syntax error : missing ‘;’ before ‘*’
2 error C2065: ‘p’ : undeclared identifier
3 error C2146: syntax error : missing ‘)’ before identifier ‘far’
4 error C2059: syntax error : ‘)’
5 error C2065: ‘p’ : undeclared identifier
these are the 5 errors I’m gettin.
First of all this program is compiler dependent can only be compiled by 16-bit compiler under windows.So if you are using Linux or modern compilers such as VC++ or 32-bit C++ compilers the program does not work.32-bit compilers do not have the concept of near,far huge pointers..
So this my be the cause for errors in your case
Cool dude………
wat does Oxb8000000 do….
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